So I am currently working on the following math problem: Find all zeros of the function f(x)=3x^3+18x^2+33x+18.?

Science & Mathematics by Anonymous 2018-07-05 18:03:26

Social Science

4 answers

I was wondering if it is okay to simplify this function by dividing by 3 and still get the same answer.

Anonymous

Yes. You will get the same answer.
Anonymous

Ans. x=-3, x=-2, x=-1. There will be no problem, when you remove 3, for 3x^3+18x^2+33x+18=0 & x^3+6x^2+11x+6=0 should have the same solutions.
Anonymous

YES!!!! f(x) = x^3 + 6x^2 + 11x + 6 Then by 'trial & error' f(-1) = -1 + 6 - 11 + 6 f(-1) = -12 + 12 = 0 Hence x = -1 => x + 1 = 0 is one of the zeroes.
Anonymous

Yes you can. Set f(x) = 0. Then: 0 = 3x^3 + 18x^2 + 33x + 18 0 = 3(x^3 + 6x^2 + 11x + 6) 0 = 3(x + 1)(x^2 + 5x + 6) 0 = 3(x + 1)(x + 2)(x + 3). Zeros are x = -1, x = -2, and x = -3.