What is the missing coordinate (?,3/2) in the equation 5x+y=11?

Science & Mathematics by Anonymous 2018-07-07 02:04:26

Social Science

9 answers

Anonymous

5x + y = 11 We are given that y = 3/2. See it in the point? Let y = 3/2 5x + (3/2) = 11 Now, solve for x.
Anonymous

From the given equation the value of x works out as 19/10
Anonymous

5x + 3/2 = 11 5x + 3/2 = 22/2 5x = 19/2 x = 19/10
Anonymous

5x+3/2=11 X=(11-3/2)/5 X=9.5/=1.9 Answer is 1.9, coward
Anonymous

5x+y=11 → 5x=11-y → x = (11-y)/5 Here x = (11 - 3/2)/5 = (19/2)/5 = 19/10 or 1.9
Anonymous

5x + y = 11 5x + 3/2 = 11 5x = 19/2 x = 1.9
Anonymous

5x=19/2 x = 19/10
Anonymous

You have the equation and a given y. Substitute and solve for x: 5x + y = 11 5x + 3/2 = 11 Multiply both sides by 2 to get rid of the denominator: 10x + 3 = 22 Subtract 3 from both sides: 10x = 19 Divide both sides by 10: x = 19/10
Anonymous

I guess you mean that 5x + 3/2 = 11; if so, the x would be 1.9 or 19/10