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6 answers
FACTOR THE FOLLOWING DIFFERENCE OF SQUARES 169a^2-49b^2
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Anonymous
169a^2 - 49b^2 = (13a + 7b)(13a - 7b)
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Anonymous
169a^2 - 49b^2 = (13a + 7b)(13a - 7b)
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Anonymous
Remember how the difference of squares is always factored: x² - y² = (x+y)(x-y) 169a² - 49b² = (13a)² - (7b)² = (13a+7b)(13a-7b)
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Anonymous
169a^2 - 49b^2 = (13a)^2 - (7b)^2 = (13a + 7b)(13a - 7b)
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Anonymous
Remember the rule for factoring a difference of squares: x² - y² = (x + y)(x - y) In your case: Let x = 13a Let y = 7b x² = (13a)² = 169a² y² = (7b)² = 49b² Hence: (13a + 7b)(13a - 7b)
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Anonymous
I think this is what you're looking for: (13a + 7b) * (13a - 7b)