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How do I find the limit of (9-y)/(3-√y) as y approaches 9 using the conjugate? I have been trying but can t seem to work out an answer?

Science & Mathematics by Anonymous 2018-06-08 14:31:39

Social Science

How do I find the limit of (9-y)/(3-√y) as y approaches 9 using the conjugate? I have been trying but can t seem to work out an answer?

2 answers

  • Anonymous

    (9-y)(3+√y)/(9-y) = (3+√y) lim y → 9 = 3+3 = 6 See Graph https://www.desmos.com/calculator/dl1imb...

  • Anonymous

    (9 - y) / (3 - sqrt(y)) = (9 - y)(3 + sqrt(y)) / (3 - sqrt(y))(3 + sqrt(y)) = (9 - y)(3 + sqrt(y)) / (9 - y) = 3 + sqrt(y). Now you can make y = 9. 3 + sqrt(9) = 3 + 3 = 6. The limit is 6.

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