Determine the center & radius of the circle: (x-2)^2=20-(y+2)^2?

Science & Mathematics by Anonymous 2018-06-01 11:02:40

Social Science

5 answers

Anonymous

C: (x-2)^2 + (y+2)^2 = (2rt5)^2. C is a circle, center (2,-2), radius 2rt5.
Anonymous

(x - 2)^2 = 20 - (y + 2)^2 (x - 2)^2 + (y + 2)^2 = 20 center | (2, -2) radius | 2 sqrt(5) ≈ 4.47214
Anonymous

(x-2)^2=20-(y+2)^2 => (x-2)^2+(y+2)^2=20 => the center=(2,-2) radius=2sqr(5)
Anonymous

(2,-2) r =2√5
Anonymous

Put the equation into center-radius form (x-h)² + (y-k)² = r² Then (h,k) is the center and r is the radius. (x-2)² = 20-(y+2)² (x-2)² + (y+2)² = 20 center at (2,-2) radius = √20 = 2√5