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To 1 decimal place, what is the perimeter of a square whose area is 628cm^2?

Education & Reference by Anonymous 2018-05-12 16:12:23

Social Science

To 1 decimal place, what is the perimeter of a square whose area is 628cm^2?

3 answers

  • Anonymous

    4√628 = 4√(4·157) = 4·2√157 = 8√157 you can do the math

  • Anonymous

    Area = side x side which means x^2 = 628 x = √628 ≈ 25.06 perimeter = 4x = 4(25.06) = 100.2 cm ;)

  • Anonymous

    A square of side x has perimeter of 4x and an area of x^2; if x^2 = 628 cm^2 then x = (628)^0.5 cm so the perimeter is (4)[(628)^0.5 cm ]

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