Anonymous

Slope of AB is 1 and slope of CD is -1 therefore both lines are perpendicular to each other.

Anonymous

For gradients to perpendicular Then mm' = -1 Where 'm' & 'm'' are the gradients. m(AB) = (6-8)/(1-3) = -2/-2 = 1 m(CD) = (-6 - 1)/(4 - -3) = -7/7 = -1 Hence mm' = 1 x -1 = -1 So AB is perpendicular t o CD

Anonymous

---> AB = 2i + 2j ----> CD = - 7i + 7 j ---> ----> AB • CD = - 14 + 14 = 0 ----> ----> Thus AB is perpendicular to CD

Anonymous

Slope of AB: (8 - 6) / (3 - 1) = 2/2 = 1. Slope of CD: (1 - (-6)) / (-3 - 4) = 7/-7 = -1. You got negative reciprocal slopes, so these lines (or segments) are perpendicular.

Anonymous

yes it is....use dot product of vectors

Anonymous

Use slopes. Two lines with slopes m1 and m2 are perpendicular if m1*m2 = -1. m1 = (8 - 6) / (3 - 1) = 1 .... slope of line AB m2 = [1 - (-6)] / (-3 - 4) = -1 ..and you find that m1*m2 = 1*-1 = 1. AB is perpendicular to CD.

Anonymous

If it is perpendicular, AB and CD will have opposite reciprocal slopes. Slope AB = (8 - 6) / (3 - 1) = 2/2 = 1 Slope CD = (1 - -6) / (-3 - 4) = 7/ (-7) = -1 which is the opposite reciprocal of 1 so AB is Perpendicular to CD