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Science & Mathematics by Anonymous 2018-05-18 11:07:12
Social Science
The equation of a parabola is given. y = 1/6x^2 + 2x + 11?
3 answers
What are the coordinates of the vertex of the parabola? Enter your answer in the boxes.
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Anonymous
x = -b/2a x = -2/2(1/6) x = -2/(1/3) x = -2(3)/(1/3)(3) x = -6/1 x = -6 The vertex is the point (x, y). y = (1/6)(-6)^2 + 2(-6) + 11 y = (1/6)(36) - 12 + 11 y = 6 - 12 + 11 y = 6 - 1 y = 5 The vertex is (-6, 5).
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Anonymous
Vertex occurs at x = -b/2a -2/(2(1/6)) = -6 y = (1/6)((-6)^2)) +2(-6) +11 = 5 Vertex: (x,y) = (-6 , 5)
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Anonymous
dy/dx = 2(1/6)x + 2 = 0 x/3 + 2 = 0 x/3 = -2 x = -6 Hence y = (1/6)(-6)^2 + 2(-6) + 11 y = -6 - 12 + 11 y = -7 Hence coordinates are (-6, -7)
