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Science & Mathematics by Anonymous 2018-06-28 04:35:46
Social Science
The velocity of a particle, v m/s, at time t seconds is given by v = 4t - 2t². If the particle moves from rest to rest, find ...?
3 answers
find the total distance travelled? I don't understand what rest to rest means. Does it mean when from the start (t = 0) to when the displacement is 0 again? ∫ v dt = s = 2t² - 2t³/3
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Anonymous
v = 4t -2t^2 At rest, v = 0 0 = 4t -2t^2 0 = 2t(2 -t) t = 0 , 2 Find the distance travelled from t = 0 to t = 2
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Anonymous
It means from t = 0 to t = 2 (where v is again 0). I agree that the integral of (4t - 2t^2) dt is 2t^2 - 2t^3/3; plugging in t = 2 and 0 gives you 8/3, and that's how far the particle travels in the time interval t = 0 to 2.
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Anonymous
v = 0 when t=0 and t=2. So integrate from t=0 to t=2' Answer = 8/3 m