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Science & Mathematics by Anonymous 2018-07-02 13:33:40
Social Science
Find x so that x-3, 3x+1,6x-5 are consecutive terms of an arithmetic sequence?
5 answers
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Anonymous
The value of x is 10 and the nth term of the sequence is 24n-17 with the 1st three terms being 7, 31, 55
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Anonymous
(3x + 1) - (x - 3) = (6x - 5) - (3x + 1) 2x + 4 = 3x - 6 10 = x
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Anonymous
The sequence needs a common difference. 6x - 5 - (3x + 1) = 3x + 1 - (x - 3) 3x - 6 = 2x + 4 x = 10
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Anonymous
2x+2=x-3+6x+5 2x-x-6x=0 -5x=0 x=0
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Anonymous
(x - 3), (3x + 1), (6x - 5) are consecutive terms of an arithmetic sequence. (3x + 1) - (x - 3) = (6x - 5) - (3x + 1) 2x + 4 = 3x - 6 x = 10 The consecutive terms of the arithmetic sequence are 7, 31 and 55.