You have questions? We got answers!

HELP IT'S MATH?

Science & Mathematics by Anonymous 2018-07-04 03:33:27

Social Science

HELP IT'S MATH?

5 answers

I need help with this problem, please and thank you!! "One side of a rectangle is sixteen inches shorter than four times another side of the rectangle. Find the sides if we also know that the area of the rectangle is 128 in2."

  • Anonymous

    Let sides be L and B L = 4B - 16 L B = 128 [ 4B - 16 ] B = 128 4B^2 - 16B - 128 = 0 B^2 - 4B - 32 = 0 [ B - 8 ] [ B + 4 ] = 0 B = 8 inches, L = 16 inches

  • Anonymous

    The area is 128 = 2^8 The sides are x and 4x-16, so both these numbers are reasonably integer powers of 2 4x-16 is an integer power of two when 4x-16 = 16, so 4x=32. and x = 8. The two sides are 8 inches and 16 inches.

  • Anonymous

    x(4x-16)=128 4x^2-16x-128=0 x^2-4x-32=0 (x-8)(x+4)=0 x = 8 in sides are 8 in and 16 in

  • Anonymous

    L = 4W-16 LW = 128 (4W-16)W = 128 4W² - 16W - 128 = 0 W = 8 in L = 4W-16 = 16 in

  • Anonymous

    x = 4y - 16 x * y = 128 (4y - 16) * y = 128 4 * (y - 4) * y = 128 y * (y - 4) = 32 y^2 - 4y = 32 y^2 - 4y + 4 = 32 + 4 (y - 2)^2 = 36 y - 2 = -6 , 6 y = -4 , 8 y > 0 y = 8 x = 4y - 16 x = 4 * 8 - 16 x = 32 - 16 x = 16 16 inches by 8 inches

ReCapcha
Not a bot