Find the derivative of sin(x^3+3)?

Science & Mathematics by Anonymous 2018-05-25 13:04:14

Social Science

6 answers

Math Calculus

Anonymous

d/dx(sin(x^3 + 3)) = cos(x^3 + 3) * d/dx(x^3 + 3) = 3x^2cos(x^3 + 3)
Anonymous

chain rule
Anonymous

y=sin(x^3+3) Hence y' =d{sin(x^3+3)}/dx =cox(x^3+3)d{(x^3+3)}/dx ={cox(x^3+3)}(3x²) y' =3x²cos(x³+3)
Anonymous

if y = sin(u(x)) then y'(x) = u'(x) cos(u(x)) so the first derivative of sin(x³+3) is 3x² cos(x³+3)
Anonymous

y = sin(x³+3) dy/dx = cos(x³+3)·3x²
Anonymous

y = sin(x^3+3) y' = cos(x^3+3) d/dx (x^3+3) y' = cos(x^3+3) (3x^2) y' = 3x^2 cos(x^3+3)