Anonymous

Yes.

Anonymous

(4-x)/(x-5) > 1/(1-x) (4-x)(1-x)>(x-5) 4 - 4x - x + x² > (x-5) x² -6x + 9 > 0 (x-3)² > 0 For f(x)^n > 0 if n is even then f(x)<0 or f(x)>0 (x-3)² > 0 gives x-3<0 or x-3>0 x<3 or x>3 <-solution set In interval notation.... (-∞,-3) U (3,+∞)